How many moles of bacl2 are formed in the neutralization of 393 ml of 0.171 m ba(oh)2 with aqueous hci

Explanation:

As there are 1000 mL present in 1 L. So, 393 ml will be equal to 0.393 L. And, concentration of present is 0.171 M.

As molarity is the number of moles present in liter of solution.

                Molarity =

Therefore, putting the given values to calculate the number of moles as follows.

          Molarity =

          0.171 M =    

            no. of moles =  

Thus, we can conclude that the number of moles of formed are .

Explanation:

Hello,

In this case, the stoichiometry is given by the undergoing chemical reaction which is:

Now, as the neutralization is carried out to completion, the resulting moles of barium chloride are given by the following stoichiometric relationship including the molarity unit, considering the 1 to 1 relationship between barium hydroxide and barium chloride and that the volume is used in liter rather than in milliliters:

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  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

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