What volume of a 0.750 m solution of hydrochloric acid a solution of hcl can be prepared from the hcl produced by the reaction of 25.0 of nacl with an excess of sulphuric acid?
nacl + h2so4 ? hcl + nahso4

0.570 L

Explanation:

Given:

Concentration of the HCl solution = 0.750 M

Mass of NaCl in the reaction = 25.0

Number of moles of NaCl in the reaction = Mass of NaCl / Molar mass of NaCl

also,

Molar mass of NaCl = 22.98 + 35.45 = 58.43 grams

thus,

Number of moles of NaCl in the reaction = 25 / 58.43 = 0.4278 moles

now,

1 mol of NaCl reacts to form 1 mol of HCl

thus,

0.4278 moles of NaCl reacts to form 0.4278 mol of HCl

also,

Concentration = Moles / volume of solution

0.750 = 0.4278 / volume of solution

or

volume of solution = 0.570 L

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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