3.0.2640 g of sodium oxalate is dissolved in a flask and requires 30.74 ml of potassium permanganate to titrate it to turn pink end point. the equation for this reaction is: 5na, c,o4+ 2kmno,+ 8h, so 2mnsog+ k, so,+ 5 na, so,+ 10co2+ 8h2o a) how many moles of sodium oxalate are present in the flask?

0.001970 moles of sodium oxalate are present in the flask.

Explanation:

Mass of sodium oxalate = m = 0.2640 g

Molar mass of sodium oxalate = = 134 g/mol

Moles of compound:n

Number of moles of sodium oxalate:

0.001970 moles of sodium oxalate are present in the flask.

answer: a chemical reaction

explanation:

im not wrong

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml