Select the true statement. 0/1 point o the amount of product formed is determined by the excess reagent. the limiting reagent will always be the substance present in the smaller amount. o the amount of product formed is determined by the limiting reagent. the limiting reagent will always be the substance present in the larger amount. incorrect

The amount of product formed id determined by the limiting reagent.

Explanation:

In a chemical reaction multiple reagents might participate. The equation of the reactions tells us how much of each reagent is needed and much product will be produced.

For example CH4 + 2 O2 => CO2 + 2 H2O

Here one molecule of methane reacts with two molecules of oxygen to for one molecule of carbon dioxide and two molecules of water.

By checking the atomic weights in the periodic table we know that 16 mols of CH4 would react with 64 mols of oxygen to form 44 mols of CO2 and 36 mols of water.

However these are perfect stechiometric ratios. In reality one or more reagents might be in excess. That excess will be left unreacted.

For example 20 mols of CH4 reacting with 64 mols of O2 would produce 44 mols of CO2, 36 mols of water and leave a leftover of 4 mols of CH4. In this case the oxygen was the limiting reagent. Note in this case that the limiting reagent was actually present in a larger amount than the excess reagent.

Depending on the molecular weights and the peculiarities of the chemical equation of the reaction either the limiting or the excess reagent might be in a larger amount.

b.

the accuracy of the data.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2