Consider the equilibrium of al(oh)3 (s) in water. al(oh)3 (s) = a13+ (aq) + 30h" (aq) how is the solubility of al(oh)3 affected by adding hcl to the solution? does the solid become more or less soluble? explain using equilibrium and the ksp.

Solid become more soluble

Explanation:

The given reaction:

On the addition of HCl to the equilibrium, the equilibrium will shift towards right which means more dissociation of aluminum oxide. This is because the furnished hydroxide ions from aluminum oxide on dissolution now binds with the protons furnished by the acid to form water and thus there become less concentration of the hydroxide ions on the right side and to nullify this effect, the equilibrium will shift in right direction.

Solubility product is defined as the product of the concentration of the ions of the solid. More the solubility product more is the solubility.

Thus, on addition of the acid, the solid become more soluble.

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

2b2t

explanation:

2b2t