The first-order decomposition of cyclopropane has a rate constant of 6.7 * 10-4 5-1. if the initial concentration of cyclopropane is 1.33 m, what is the concentration of cyclopropane after 644 s? oa) 0.43 m b) 0.15 m c) 0.94 m d) 0.86 m

D) 0.86 M

Explanation:

Given that:

The rate constant, k = 6.7×10⁻⁴ s⁻¹

Initial concentration [A₀] = 1.33 M

Time = 644 s

Using integrated rate law for first order kinetics as:

Where,

is the concentration at time t

So,

answer is a

explanation:

air

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then a couple days later you check the air pressure in the tire

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