What is the percentage of a weak acid (pka = 5.4) in the non-ionized form in plasma (ph 7.4)?

0.99%

Explanation:

The Henderson-Hasselbalch equation relates the ratio of the ionized to the non-ionized form of an acid as follows:

pH = pKa + log([A⁻]/[HA])

Inserting the values for pH and pKa and solving gives:

7.4 = 5.2 + log([A⁻]/[HA])

2 = log([A⁻]/[HA])

[A⁻]/[HA] = 100/1

The percentage of the weak acid in non-ionized form (HA) is then calculated:

[HA]/([A⁻] + [HA]) = 1/(100+1) x 100% = 0.99&

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.