In a triprotic acid, which ka has the lowest value? a) kat b) ka2 c) ka3 d) kb1

A) Ka1

Explanation:

Dissociation constant of an acid shows the amount of the acid dissociated to furnish hydrogen ions.

The more the dissociation constant, the more stronger is the acid.

Generally for a polyprotic acids,

The first dissociation constant, Ka1 is large. After the dissociation of the first proton, the dissociation of more protons is suppressed as the equilibrium shifts to the acid side.

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.