Chemistry, 29.08.2019 18:30, lai16kk77

Which of the following is a proton donor. a. bronsted-lowry base 6 bronsted-lowry acid c. lewis acid d. lewis base

Answers: 3

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answered: mrtroll3289

Bronsted-Lowry acid

Explanation:

Bronsted-Lowry Base -

According to Bronsted-Lowry theory of acids and bases:

Acids are those substances which donate proton in the solution whereas bases are those substances which accept proton in the solution.

Consider an example,

$HCO_3^{-} + HOH\; \rightarrow H_2CO_3 + OH^{-}\\$

HCO3- behave as base as it accepts proton in the reaction whereas HOH behaves as acid as it releases proton.

According to Lewis theory of acids and bases:

Acids are electron acceptor and bases are electron donar. Acids are generally electron deficient species whereas Lewis are chemical species having lone pair of electrons.

For example, AlCl3 is behave as Lewis acid because of being electron deficient species.

NH3 is a Lewis base because of presence of lone pair of electrons.

Therefore, among given options, Bronsted-Lowry acid is the correct option.

answered: Guest

away from the curb

explanation:

the wheels would then hit the curb if it started to rolling, decreasing the chance of an accident.

answered: Guest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.