Nitrosyl bromide decomposes according to the following equation. 2nobr (g) 2no (g) br2 (g) a sample of nobr (0.64 mol) was placed in a 1.00-l flask containing no no or br2. at equilibrium the flask contained 0.46 mol of nobr. how many moles of no and br2, respectively, are in the flask at equilibrium

Moles of NO = 0.18

Moles of Br2 = 0.18

Explanation:

The given reaction with ICE table is:

Initial          0.64                    -      -

Change      -2x                    +2x    +x

Equilb        (0.64-2x)               2x    2x

At equilibrium:

[NOBr] = 0.64-2x

NO = Br2 = 2x

The equilibrium moles of NOBr  = 0.46

Moles of NO = Moles of Br2 = 2x = 2(0.09) = 0.18 moles

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.

sorry i was late, but i don't know what assignment your talking about, i'm in flvs as well, im in earth space science. but u are behind pace bc every class should be in the 3's or 4'