Arrange the following substances in order of increasing boiling point ch3oh, ch4, ch3ch2oh, hoch2ch2oh multiple choice o ch3oh

The answer is: CH₄ < CH₃OH < CH₃CH₂OH < HOCH₂CH₂OH

Explanation:

Boiling point refers to the temperature at which the pressure exerted by the surrounding on the liquid is equal to the vapor pressure of the liquid. The boiling point increases as the molar mass of the substance increases.

Since the molar mass increases in the order:

CH₄ < CH₃OH < CH₃CH₂OH < HOCH₂CH₂OH

Therefore, the order of increasing boiling point:

CH₄ < CH₃OH < CH₃CH₂OH < HOCH₂CH₂OH  

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

i think the answer is terrae but not 100 percent sure. ▓▬▬ §