If a cigarette contains 25 mg of tar, how many cigarettes must a person smoke to inhale 1.0 pounds of tar?

The answer is = 5.51 exp -5 pounds

Explanation:

1mg is 2.2046e-6 pounds,

Thus 25mg is * 25 *2.2046e-6 = 5.51 exp -5 pounds

So that a person can inhale 1.0 pound of tar must smoke 181488.2033 cigarrettes

Explanation:

⇒ 1.0 pound * ( mg / 2.204 E-6 pounds) = 4537205.082 mg of tar

⇒ # cigarrete = 4537205.082 mg * ( 1 cigarrtte / 25 mg )

⇒ # cigarrete = 181488.2033 cigarrettes

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6