Determine the number of moles of the compound and determine the number of moles of each type of atom in each of the following. a. 25.0 g of propylene, c3h6b. 3.06 x 10^-3g of the amino acid glycine, c2h5no2c. 25 lb of the herbicide treflan, c13h16n2o4f (1lb = 454 g)d. 0.125 kg of the insecticide paris green, cu4(aso3)2(ch3co2)2e. 325 mg of aspirin, c6h4(co2h)(co2ch3)
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Chemistry, 22.06.2019 17:10, sophiaa23
)benzene and toluene form nearly ideal solutions. consider an equimolar solution of benzene and toluene. at 20 °c the vapour pressures of pure benzene and toluene are 9.9 kpa and 2.9 kpa, respectively. the solution is boiled by reducing the external pressure below the vapour pressure. calculate (i) the pressure when boiling begins, (ii) the composition of each component in the vapour, and (iii) the vapour pressure when only a few drops of liquid remain. assume that the rate of vaporization is low enough for the temperature to remain constant at 20 °c.
Answers: 1
Chemistry, 22.06.2019 18:30, bibiansolis
The table lists the lattice energies of some compounds. compoundlattice energy (kj/mol)lif –1,036licl –853naf –923kf –821nacl –786which statement about crystal lattice energy is best supported by the information in the table? the lattice energy increases as cations get smaller, as shown by lif and kf. the lattice energy increases as the cations get larger, as shown by lif and licl. the lattice energy decreases as cations get smaller, as shown by nacl and naf. the lattice energy decreases as the cations get smaller, as shown by naf and kf.
Answers: 3
Chemistry, 22.06.2019 19:00, montgomerykarloxc24x
Convert the temperature of dry ice, –77 ∞c, into degrees fahrenheit and kelvin.
Answers: 2
Chemistry, 22.06.2019 20:30, lexibyrd120
Water undergoes a large change in density at 0 ∘ c as it freezes to form ice. calculate the percent change in density that occurs when liquid water freezes to ice at 0 ∘ c given that
Answers: 2
Determine the number of moles of the compound and determine the number of moles of each type of atom...
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