Chemistry, 28.08.2019 01:30, lexi8938

Acompound with molecular formula c5h10o2 has the following 1h nmr spectrum: 1.15 (t, 3h), 1.25 (t, 3h), 2.33 (q, 2h), 4.13 (q, 2h). draw its structure. hint: how many rings and π bonds does c5h10o2 have

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answered: UltimateGoal

Ethyl propionate

Explanation:

Calculating the double bond equivalence as:

DBE = C - (H/2) - (X/2) + (N/2) +1

Where

C is the number of carbon atoms

N is the number of nitrogen atoms

X is the number of halogens

H is the number of hydrogen atoms

So, according to the formula, $C_5H_{10}O_2$

DBE = 5 - (10/2) - (0/2) + (0/2) +1 = 1

It means there is one double bond or one ring.

from the NMR signal, it is clear that compound has two triplet and two quardrate group that means two -CH3 and two -CH2 groups are present.

From the splitting information, it is clear that each the -CH2- group is next to a -CH3, and vice-versa. In this case ring structure is not possible.

The chemical shift of two protons 4.13 ppm(q, 2H) is for protons next to an O atom, therefore, compound must have

-OCH_2CH_3 .

Then the signal at 2.33 is for a -CH2-group next to a C=O. So compound must have a structure CH3-CH2-C=O. Now, there is only one way to complete the structure - by bonding the O to the C=O carbon.

So the compound is ethyl propionate

Acompound with molecular formula c5h10o2 has the following 1h nmr spectrum: 1.15 (t, 3h), 1.25 (t,

answered: Guest

there are no statements provided but here is why:

sulfur belongs to group 16 because it can be found in nature whether it is in a free or combined state.

hope this

answered: Guest

For cyclohexane compounds drawn in a chair conformation: -axial bonds are vertical -equatorial bonds are parallel to two bonds within the ring. thus, as i assume the chair conformation is drawn: -the x group is in an axial position, as are the five other vertical bonds. -three axial bonds are on the top face of the ring -the other three axial bonds are on the bottom face the position of the second substituent on each ring carbon is equatorial. gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other. drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1. click this link and watch some academic videos that may you more understand the topic

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Acompound with molecular formula c5h10o2 has the following 1h nmr spectrum: 1.15 (t, 3h), 1.25 (t,...