Determine whether each compound is soluble or insoluble. if the compound is soluble, list the ions present in solution. agno3 pb(c2h3o2)2 kno3 (nh4)2s

According to the solubility rules:

1. Silver nitrate: AgNO₃ is soluble.

Reason: Nitrates (NO₃⁻) are soluble.

AgNO₃ (aq) → Ag⁺(aq) + NO₃⁻(aq)

Ions present: silver ion (Ag⁺) and nitrate ion (NO₃⁻)

2. Lead(II) acetate: Pb(C₂H₃O₂)₂ is soluble.

Reason: Acetates (C₂H₃O₂⁻) are soluble

Pb(C₂H₃O₂)₂ → Pb²⁺(aq) + 2 CH₃COO⁻(aq)

Ions present: lead(II) ion (Pb²⁺) and two acetate ions (CH₃COO⁻)

3. Potassium nitrate: KNO₃ is soluble.

Reason: Nitrates (NO₃⁻) are soluble and group-1 ions such as K⁺ are soluble.

KNO₃ (aq) → K⁺(aq) + NO₃⁻(aq)

Ions present: potassium ion (K⁺) and nitrate ion (NO₃⁻)

4. Ammonium sulfide: (NH₄)₂S is soluble.

Reason: Ammonium (NH₄⁺) ions are soluble

(NH₄)₂S (aq) → 2 NH₄⁺(aq) + S²⁻(aq)

Ions present: two ammonium ions (NH₄⁺) and sulphide ion (S²⁻)

20 drops hope this

i just calculated it all out, and not including weekends, and all the different days off. as of this school year (2018-2019) students are spending 2198 hours in school this year