If you purchased 2.31 μci of sulfur-35, how many disintegrations per second does the sample undergo when it is brand new?

8.547 x 10⁴disintegrations per second

Explanation:

To calculate the disintegrations per second as -

Given ,

2.31 μCi of sulfur  -35 .

Since ,

1 Ci = 3.7 * 10 ¹⁰ Bq

1 μCi = 10 ⁻⁶ Ci

Hence ,

conversation is done as follows -

2.31 ( 1 * 10⁻⁶) * ( 3.7 * 10¹⁰)

= 8.547 x 10⁴

Hence ,

8.547 x 10⁴disintegrations per second , the sample undergo for it to be brand new .

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of c is as shown here in the image.

the answer is 0.8m.

by: nicholas