If you purchased 2.31 μci of sulfur-35, how many disintegrations per second does the sample undergo when it is brand new?

8.547 x 10⁴disintegrations per second

Explanation:

To calculate the disintegrations per second as -

Given ,

2.31 μCi of sulfur  -35 .

Since ,

1 Ci = 3.7 * 10 ¹⁰ Bq

1 μCi = 10 ⁻⁶ Ci

Hence ,

conversation is done as follows -

2.31 ( 1 * 10⁻⁶) * ( 3.7 * 10¹⁰)

= 8.547 x 10⁴

Hence ,

8.547 x 10⁴disintegrations per second , the sample undergo for it to be brand new .

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."

they are made of gases.

they have a spherical shape.

they make energy through fusion.