Astudent collects 625 ml of oxygen at a temperature of 24°c and a pressure of 0.899 atm. how many moles of oxygen did the student collect?

0.023 moles

Explanation:

Given that:

Pressure = 0.899 atm

Temperature = 24 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (24 + 273.15) K = 297.15 K

Volume = 625 mL

Also, 1 mL = 10⁻³ L

So, volume = 0.625 L

Moles of the gas = ?

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.899 atm × 0.625 L=n × 0.0821 L.atm/K.mol ×  297.15 K

⇒n = 0.023 moles