What is the final volume in milliliters when 0.918 l of a 44.0 % (m/v) solution is diluted to 21.8 % (m/v)?

1852.844 mL

Explanation:

The volume of 44% solution used to make the mixture = 0.918 L

Let the volume of 21.8% solution used to make the mixture = x L

For 44% acid solution:

C₁ = 44% , V₁ = 0.918 L

For 21.8% acid solution :

C₂ = 21.8% , V₂ = x L

Using  

C₁V₁ = C₂V₂

44×0.918 = 21.8×x

Solving for x, we get:

x = 1.852844 L

Final volume in mL as:

1  L = 1000 mL

Thus, final volume = 1852.844 mL

that's what i got you can count the number of atoms

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.