Apressure of 3 atm was required to force water through an initially dry teflon membrane of uniform pore size. determine the pore size. (theta_water = 110 degree, gamma_water = 73mn/m)

Explanation:

As it is given that = 3 atm =

                r = 73 mN/m

            =

As it is known that free energy of a wetting liquid in a solid-liquid interface is lower than the solid-gas interface free energy.

As a result, there will be spontaneous filling of pores but we need a non-reactive gas under the pressure so that the liquid can be forced out of the pores.

The pressure difference will be represented as . Hence, work done by the gas to increase interface free energy is as follows.

where,   = incremental volume of gas in the pore

                   dS = incremental solid-gas interface area due to .

So,             =

Therefore, formula to calculate pore size is as follows.

                       D =

Putting the given values into the above formula as follows.

                        D =

                            =

                             =

Thus, we can conclude that pore size is .                                                

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2