Asample containing kbr (m 119& /mol) and kno3 (m 101 g/mol) was analysed by using the mohr method, a 1.1250-g sample is dissolved into 200.0 ml solution (solution a). 20.00-ml. of solution a was titrated with 16.25 ml of 0.oson agnos (m 170) solution. a) report c of ca solution & according to the tination data b) calculate c% w/w of kbr in the original sample.

Explanation:

(a)   As we know that relation between normality and volume of two solutions is as follows.

As the given data is as follows.

              = ?,               = 0.050 N

              = 20 ml,       = 16.25 ml

Therefore, putting the given values into the above formula as follows.

                = 0.0406 N

Hence, normality of solution A is 0.0406 N.

(b)   As gram equivalent weight of KBr is 119 g/mol.

Formula to calculate normality is as follows.

              Normality =

As volume is 200 ml, normality is 0.0406 N, and gram equi. wt is 119 g/mol. Therefore, putting these values into the above formula as follows.

          Normality =      

          0.0406 N  =

              weight = 0.9668 g

As 0.9668 g of KBr is present in 1.1250 g sample. Hence, weight percentage will be calculated as follows.

                   Weight % of KBr =

                                               = 85.94%

Thus, we can conclude that C% w/w of KBr in the original sample is 85.94%.

frequency, z, and the collision density, z, in carbon dioxide (co2), r 180 pm at 30 °c and 120 kpa