The henry's law constant (kh) for o2 in water at 20°c is 1.28e-3 mol/l atm. how many grams of o2 will dissolve in 3.5 l of h2o that is in contact with pure o2 at 1.65 atm?

Answer : The mass of dissolved will be, 0.2365 grams

Explanation :

First we have to calculate the concentration of .

As we know that,

where,

= concentration of = ?

= partial pressure of = 1.65 atm

= Henry's law constant =

Now put all the given values in the above formula, we get:

The concentration of =

Now we have to calculate the moles of

Now we have to calculate the mass of

Therefore, the mass of dissolved will be, 0.2365 grams

i would say b

explanation:

but i think i would need more information than that