Avolume of 500.0 ml of 0.220 m hcl(aq) was added to a high quality constant-pressure calorimeter containing 500.0 ml of 0.200 m naoh(aq). both solutions have a density of 1.000 g ml-1 and a specific heat of 4.184 j g‑1 oc-1. the temperature of the entire system rose from 25.60 °c to 26.70 °c. calculate the heat of reaction, in kj, per mole of naoh(aq).

Heat of the reaction per mole of NaOH = 46.02 kJ/mol

Explanation:

The reaction between HCl (strong acid) and NaOH(strong base) is a neutralization reaction which yields a salt NaCl and water

The heat (q) of a reaction is given as:

where m = mass of the system

c = specific heat

T1 and T2 are the initial and final temperatures

It is given that:

Volume of HCl = 500.0 ml

Volume of NaOH = 500.0 ml

Density of HCl and NaOH = 1.000 g/ml

Total mass of the solutions, m = 500.0 +500.0 = 1000.0 g

c = 4.184 J/g/c

T1 = 25.6 C

T2 = 26.70 C

Substituting appropriate values in equation (1) gives:

Now, the number of moles of NaOH is:

Heat of reaction/mole NaOH is: