38. what is the expected boiling point of a solution prepared by dissolving 6.37 g of sodium iodide (nal) in 48.6 g of water (h 0)? k'b (ater)-0.512"cm a) 0.90°c d) 103.26"c b) 100.45°c e) none of the above c) 100.90°c

c) 100.90°C

Explanation:

Elevation in boiling point is given by:

= elevation in boiling point

i= vant hoff factor = 2 (for NaI[/tex]

= boiling point constant =

m= molality  

Weight of solvent i kg =48.6 g= 0.0486kg

Thus the boiling point of the solution will be .

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