According to the following reaction: khp+ naoh> nakp+ h20 used instead of glucose? water? sea water? what is the concentration of the naoh if it took 42.52 ml to titrate 0.835 g of khp? (mm khp 204.2 g/mol)

The molarity of NaOH solution is 0.096 M.

Explanation:

To calculate the number of moles, we use the equation:

Given mass of KHP = 0.835 g

Molar mass of KHP = 204.2 g/mol

Putting values in above equation, we get:

For the given chemical reaction:

By Stoichiometry of the reaction:

1 mole of KHP reacts with 1 mole of NaOH.

So, 0.00408 moles of KHP will react with = of NaOH.

To calculate the molarity of NaOH, we use the equation:

We are given:

Moles of NaOH = 0.00408 moles

Volume of solution = 42.52 mL = 0.04252L      (Conversion factor:  1L = 1000 mL)

Putting values in above equation, we get:

Hence, the molarity of NaOH solution is 0.096 M.

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when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml