A1000g ni rod, heated to 150. °c was placed in 1.00 kg of water at 25.0 °c. the final temperature of the water was 26.3 °c. what is the molar specific heat of ni? qhen gcald, cah o) 4184 j/goc

Answer : The molar specific heat of Ni is,

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

where,

= specific heat of Ni = ?

= specific heat of water =

= mass of Ni = 1000 g

= mass of water = 1 kg = 1000 g

= final temperature of water =

= initial temperature of Ni =

= initial temperature of water =

Now put all the given values in the above formula, we get

Now we have to calculate the molar specific heat of Ni.

Therefore, the molar specific heat of Ni is,

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml