What are the molar concentrations of the ions in 0.26 m aluminum sulfate?
c(a13+) =
c(so4^2-) =

c(Al³⁺) =  0.52 mol·L⁻¹; c(SO₄²⁻) = 0.84 mol·L⁻¹

Explanation:

One mole of aluminium sulfate produces 2 mol of aluminium ions and 3 mol of sulfate ions.

If we apply the same proportionality, 0.26 mol of Al₂(SO₄)₃ produces 0.52 mol of Al³⁺ions and 0.84 mol of SO₄²⁻ ions.

                      Al₂(SO₄)₃(aq) ⟶ 2Al³⁺(aq) + 3SO₄²⁻(aq)

I/mol·L⁻¹:              0.26                   0              0

C/mol·L⁻¹:           -0.26                 +0.52      +0.84

E/mol·L⁻¹:             0                        0.52        0.84

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