Chemistry

Chemistry, 06.08.2019 21:30, glowbaby123

What is the meaning or member?
me .

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English, 20.07.2019 07:40, maayajskkcc

You are a member of a gang & you have been arrested with another member of your gang.both of you are confined away from each other and you have no way of communicating with other member.the police does not have enough evidence to convict both of you with major charges & instead offer you and the other member a bargain. you have 2 choices : a) you have remain silentb) or betray other member & testify that he has committed the crime.

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Mathematics, 03.08.2019 01:30, babyjulie61

The given two-parameter family is a solution of the indicated differential equation on the interval (−∞, ∞). determine whether a member of the family can be found that satisfies the boundary conditions. y = c1x2 + c2x4 + 3; x2y'' − 5xy' + 8y = 24 (a) y(−1) = 0, y(1) = 8 a member can be found. a member cannot be found. (b) y(0) = 8, y(1) = 5 a member can be found. a member cannot be found. (c) y(0) = 3, y(1) = 0 a member can be found. a member cannot be found. (d) y(1) = 3, y(2) = 15 a member can be found. a member cannot be found.

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Mathematics, 18.08.2019 20:50, babyboogrocks5695

The gym offers a discount when more than one member of the family joins.the first member ( n=10) pays $550 per year. the second member to join (n=1) get discount of $75 per yar. the third member (n=2) gets an additional $75. the price for the nth member is given by 550+(-75n)a. what is the price for the fourth member to join (n=3)b. for a large family,is it possible for a member to would join free? if so, which member would it be? explain you reasoningc. other than $0, what is the lowest amount that member would pay to join? which member would it be? explain your reasoning

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Mathematics, 21.08.2019 19:20, hannahkharel2

The given two-parameter family is a solution of the indicated differential equation on the interval (−∞, ∞). determine whether a member of the family can be found that satisfies the boundary conditions. y = c1x2 + c2x4 + 3; x2y'' − 5xy' + 8y = 24 (a) y(−1) = 0, y(1) = 8 a member can be found. a member cannot be found. (b) y(0) = 8, y(1) = 5 a member can be found. a member cannot be found. (c) y(0) = 3, y(1) = 0 a member can be found. a member cannot be found. (d) y(1) = 3, y(2) = 15 a member can be found. a member cannot be found.

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