If you combine 27.1 g of a solute that has a molar mass of 27.1 g/mol with 100.0 g of a solvent, what is the molality of the resulting solution?

The molality of the solution is 0.1 m.

Explanation:

To calculate the molality of solution, we use the equation:

Where,

= Given mass of solute = 27.1 g

= Molar mass of solute = 27.1 g/mol

= Mass of solvent = 100 g

Putting values in above equation, we get:

Hence, the molality of the solution is 0.1 m.

the molality of the solution is 10 mol/kg

Explanation:

To find the molality of a solution we apply the following formula

data:

100 g of solvente

We have the amount of solvent expressed in grams but to be able to use the data in the formula we must pass it to kilograms

we apply a simple rule of three

27.1g of solute, molar mass 27.1 g/mol

We need the moles of solute and they give us grams of solute and molar mass

The molar mass is 27.1 g / mol This means that there is 27.1 g for each mol of solute.

The amount of solute we have is 27.1g and according to the molar mass this amount of solute corresponds exactly to 1 mole

Therefore having 27.1 g of solute is equivalent to saying that we have 1 mol of solute

Now that we have the data in the correct units we apply the formula

the molality of the solution is 10 mol/kg

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