If you take organic chemistry laboratory (chm2211l) you will learn the term reflux. a reaction is considered to be at reflux when it is set at the boiling point of your solvent. a. in order to bring 74.81 ml of chloroform (density = 1.4832 g/cm3 , c = 0.96 j/g*k ) to reflux from room temperature (25 oc) it requires 1.46 kj of energy. what will be the temperature (in of) of the chloroform?

Answer : The temperature of the chloroform will be,

Explanation :

First we have to calculate the mass of chloroform.

conversion used :

Now we have to calculate the temperature of the chloroform.

Formula used :

where,

q = amount of heat or energy = 1.46 kJ = 1460 J   (1 kJ = 1000 J)

= specific heat capacity =

m = mass of substance = 110.958 g

= final temperature = ?

= initial temperature =

Now put all the given values in the above formula, we get:

Now we have to convert the temperature from Kelvin to Fahrenheit.

The conversion used for the temperature from Kelvin to Fahrenheit is:

As we know that, or,

 ...........(1)

Now put the value of temperature of Kelvin in (1), we get:

Therefore, the temperature of the chloroform will be,

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

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explanation: