Im studying this and i dont know what to do for my exam. write the net ionic equation for the reaction which occurs when silver nitrate (agno3) reacts with sodium chloride (nacl) to form a precipitate. include
states in the equation.

sodium chloride (nacl) and silver nitrate (agno3) are both solids that are highly soluble in water.   they give a double displacement reaction where the ions switch places and give sodium nitrate (nano3) and silver chloride (agcl) as the products.   silver nitrate is also very soluble in water, but silver chloride is highly insoluble in water and will precipitate out of solution as a white solid.   the balanced chemical equation is written below.

nacl (aq) + agno3 (aq) --> agcl (s) + nano3 (aq)

so two colorless solutions will give a milky white suspension when mixed.

explanation:

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given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g