sodium chloride (nacl) and silver nitrate (agno3) are both solids that are highly soluble in water. they give a double displacement reaction where the ions switch places and give sodium nitrate (nano3) and silver chloride (agcl) as the products. silver nitrate is also very soluble in water, but silver chloride is highly insoluble in water and will precipitate out of solution as a white solid. the balanced chemical equation is written below.
nacl (aq) + agno3 (aq) --> agcl (s) + nano3 (aq)
so two colorless solutions will give a milky white suspension when mixed.
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mass of na = 115 g
mass of nacl produced
given reaction is-
2na(s) + cl2(g) → 2nacl(s)
since cl2 is in excess, na will be the limiting reagent
as per the reaction stoichiometry na: nacl = 1: 1
i.e. moles of na reacted = moles of nacl formed
now, # moles of na = mass of na/atomic mass
= 115 g/23 g.mol-1 = 5 moles
therefore, moles of nacl = 5
molar mass of nacl = 58 g/mol
mass of nacl = 5 moles * 58 g.mol-1 = 290 g
ans: amount of nacl produced = 290 g