The decomposition of nitrogen dioxide to nitrogen monoxide and oxygen gas is a second order process as suspected in the previous question. one would expect the second half-life of this reaction to be the first half-life of this reaction.

Explanation:

For the given reaction

Now, expression for half-life of a second order reaction is as follows.

                      ....... (1)

Second half life of this reaction will be . So, expression for this will be as follows.

          =  ...(2)

where is the final concentration that is, here and is the initial concentration.

Hence, putting these values into equation (2) formula as follows.

        =

                      =     ...... (3)

Now, dividing equation (3) by equation (1) as follows.

            =                  

                                    = 3

or,                       = 3    

Thus, we can conclude that one would expect the second half-life of this reaction to be three times the first half-life of this reaction.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.