Cyclopropane, c3h6, is converted to its isomer propylene, ch2=chch3, when heated. the rate law is first order in cyclopropane, and the rate constant is 6.0 × 10−4/s at 500°c. if the initial concentration of cy- clopropane is 0.0226 mol/l, what is the concentration after 525 s?

0.011 M

Explanation:

Expression for rate law for first order kinetics is given by:

where,

k = rate constant  =

t = time taken   = 525 sec

a = initial amount of the reactant  = 0.0226 mol/L

a - x = amount left = ?

Now put all the given values in above equation, we get

Thus the concentration after 525 s is 0.011 mol/L.

16

explanation:

the marks go by 4s