Be sure to answer all parts. dichlorine heptaoxide, cl2o7, can be viewed as two clo4 groups sharing an o atom. draw a lewis structure for cl2o7 with the lowest formal charges and predict any deviation from the ideal for the cl―o―cl bond angle. be sure to include lone-pair electrons.

Explanation:

Dichlorine heptaoxide () can also be written as as one oxygen atom will be at the center and there will be two terminal groups.

This dichlorine heptaoxide is electrically neutral as there is no charge on this compound.

Number of valence electrons in an oxygen atom are 6, valence electrons in a chlorine atom are 7.

Hence, total number of valence electrons in will be as follows.

       Total valence electrons =

                                                = 56

Lewis structure of will have one oxygen atom at the center and two terminal groups. Each oxygen atom in will have 2 lone pair of electrons and oxygen atoms of groups will be attached to chlorine atoms through double bonds.

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it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.