Calculate δh for the reaction: c(graphite) + 2h 2(g) + 1/2 o 2(g) => ch 3oh(l) using the following information: c(graphite) + o 2 => co 2(g) δh o = -393.5 kj h 2(g) + 1/2 o 2 => h 2o(l) δh o = -285.8 kj ch 3oh (l) + 3/2 o 2(g) => co 2(g) + 2h 2o(l) δh o = -726.4 kj a. +238.7 kj b. -238.7 kj c. +548.3 kj d. -548.3 kj e. +904.5 kj