Enter your answer in the provided box. sodium hydroxide is used extensively in acid-base titrations because it is a strong, inexpensive base. a sodium hydroxide solution was standardized by titrating 28.58 ml of 0.1851 m standard hydrochloric acid. the initial buret reading of the sodium hydroxide was 1.98 ml, and the final reading was 30.89 ml. what was the molarity of the base solution?

Molarity of the base solution was 0.1830 M

Explanation:

Total volume of NaOH added for complete standardization = (final reading-initial reading) = (30.89-1.98) mL = 28.91 mL

Neutralization reaction between NaOH and HCl :

So, 1 mol of HCl neutralizes 1 mol of NaOH

Moles of HCl added = moles

If molarity of NaOH was C (M) then moles of NaOH added is

=            

or, C = 0.1830

So, molarity of NaOH was 0.1830 M            

i think it's c. if you look search electronic symbol on google and then click on wiki it shows you a