Chemistry, 29.07.2019 19:20, faithtunison
The reaction c4h8(g)⟶2c2h4(g) c4h8(g)⟶2c2h4(g) has an activation energy of 262 kj/mol.262 kj/mol. at 600.0 k,600.0 k, the rate constant, , is 6.1×10−8 s−1.6.1×10−8 s−1. what is the value of the rate constant at 785.0 k?
Answers: 2
![\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]](/tpl/images/0147/7591/6d953.png)
= rate constant at 
= 
= rate constant at 
= ?
= activation energy for the reaction = 262 kJ/mole = 262000 J/mole
= initial temperature = 
= final temperature = ![\log (\frac{K_2}{6.1\times 10^{-8}s^{-1}})=\frac{262000J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{600.0K}-\frac{1}{785.0K}]](/tpl/images/0147/7591/a9479.png)
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The reaction c4h8(g)⟶2c2h4(g) c4h8(g)⟶2c2h4(g) has an activation energy of 262 kj/mol.262 kj/mol. at...
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