Chemistry, 27.07.2019 04:10, culturedxnat
For dissociation of a complex insolving a simple equilibrium: ab a+ b, the equilibrium constant, k- tab is equal to the ratio of forward and reverse rate constants: kp kotl/ kon for avidin-biotin, kp- 10-15. suppose kon were as fast as the diffusion limit, -109 ms1. (a) what is the value of ko? (b) what would be the half-life of the avidin-biotin complex? (c) suppose kon for avidin-biotin were 10-m s. what would be the half-life of the complex?
Answers: 2
Chemistry, 23.06.2019 14:00, jadkins842
Ahas distinct properties and composition that never vary.
Answers: 1
Chemistry, 23.06.2019 14:20, bjbass899
Compounds a and b react to form compounds c and d according to the equation: aa + bb → cc + dd. under which conditions will the rate law be given by the equation: rate = k[a]a[b]b? a. the reaction takes place in one step. b. the reaction is endothermic. c. the reaction is exothermic. d. the reaction involves more than one step.
Answers: 3
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