The oxidation state for carbon element in co2 is:
a. +4
b. +5
c. +1
d. +3

Option A,+4

Explanation:

Oxidation state of any element is the sum of oxidation of all elements =0

Here we need to find oxidation no of carbon and consider oxidation no of carbon as X and oxidation number of oxygen is -2

Then X+2(-2)=0 (since 2 oxygen atoms are there in CO2 )

X-4=0

X=+4

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c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.