For the reaction n2o4(g) m 2 no2(g), a reaction mixture at a certain temperature initially contains both n2o4 and no2 in their standard states (see the defi nition of standard state in section 6.9 ) . if kp = 0.15, which statement is true of the reaction mixture before any reaction occurs? (a) q = k; the reaction is at equilibrium. (b) q 6 k; the reaction will proceed to the right. (c) q 7 k; the reaction will proceed to the left.

c) Q > K, the reaction will proceed to the right

Explanation:

The given reaction is:

The direction in which the above reaction will shift is based on the relation between the values of the equilibrium constant (K) and the reaction quotient (Q)

If Q = K, the reaction is at equilibrium

If Q < K, the reaction shifts to the left

If Q > K, the reaction shifts to the right

For a gas phase reaction, Q is given as:

Here,

Kp = 0.15

Qp = 1.00

Since Qp > Kp, the reaction will shift to the right

the answer to your question is c

it's all four options.