Balance the equation (nh4)3 po4 +na0h arrow na3p04 +3nh3 +3h20.

Explanation:

(NH4)3 PO4 +NaOH arrow Na3PO4 +3NH3 +3H2O

Start by seeing what happens with the Na. You need 3 on the left, so put a 3 in front of NaOH

(NH4)3 PO4 +3NaOH arrow Na3PO4 +3NH3 +3H2O  Next work with the nitrogens. YOu have 3 on the left and 3 on the right, so they are OK. Next Go to the stray oxygens.

You have 3 on left in (NaOH) and three on the right in 3H2O so they are fine as well. The last thing you should look at are hydrogens.

There are 12 + 3 on the left which is 15. There are 9 (in 3NH3) and 6 more in the water. They seem fine.

Why didn't I do something with the PO4^(-3)? The reason is a deliberately stayed away from them and balanced everything else. Since they were untouched with 1 on the left and 1 on the right, they are balanced.

Species      Na        H        O         N       PO4

Left             3          15        3         3          1

Right           3         15         3         3          1

(NH₄)₃PO₄ + 3NaOH ⟶ Na₃PO₄ + 3NH₃ + 3H₂O

Explanation:

Your unbalanced equation is

(NH₄)₃PO₄ + NaOH ⟶ Na₃PO₄ + NH₃ + H₂O

A method that usually works for balancing by inspection is

1. Pick the most complicated-looking formula [(NH₄)₃PO₄].

Put a 1 in front of it.

1(NH₄)₃PO₄ + NaOH ⟶ Na₃PO₄ + NH₃ + H₂O

2. Balance N.

We have fixed 3N on the left. We need 3N on the right.

Put a 3 in front of NH₃.

1(NH₄)₃PO₄ + NaOH ⟶ Na₃PO₄ + 3NH₃ + H₂O

3. Balance P.

We have fixed 1P on the left. We need 1P on the right.

Put a 1 in front of Na₃PO₄.

1(NH₄)₃PO₄ + NaOH ⟶ 1Na₃PO₄ + 3NH₃ + H₂O

4. Balance Na

We have fixed 3Na on the right. we need 3Na on the left.

Put a 3 in front of NaOH.

1(NH₄)₃PO₄ + 3NaOH ⟶ 1Na₃PO₄ + 3NH₃ + H₂O

5. Balance O.

We have fixed 7O on the left and 4O on the right. We need three more O atoms on the right.

Put a 3 in front of H₂O.

1(NH₄)₃PO₄ + 3NaOH ⟶ 1Na₃PO₄ + 3NH₃ + 3H₂O

All species have a coefficient. The equation should now be balanced.

6. Check that all atoms are balanced

The balanced equation is

(NH₄)₃PO₄ + 3NaOH ⟶ Na₃PO₄ + 3NH₃ + 3H₂O