Chemistry

Chemistry, 24.07.2019 11:20, ari758540

Acetic acid has a ka of 1.8ã10â5. three acetic acid/acetate buffer solutions, a, b, and c, were made using varying concentrations: [acetic acid] ten times greater than [acetate], [acetate] ten times greater than [acetic acid], and [acetate]

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Chemistry, 02.08.2019 17:20, moonlightparis9015

In lab, you will be provided with a 1.8 m acetic acid solution (ch3cooh) and solid sodium acetate trihydrate (naoocch3  3h2o). you want to make 100.0 ml of a 0.5 m acetic acid buffer at ph 5.00. how many grams of sodium acetate trihydrate, and what volume (ml) of the 1.8m acetic acid solution and deionized water should you combine? the pka of acetic acid is 4.75. show all work. (6 pts)

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Chemistry, 10.09.2019 18:30, hayleneolide

Buffer preparation. you wish to prepare a buffer consisting of acetic acid and sodium acetate with a total acetic acid plus acetate concentration of 250 mm and a ph of 5.0. what concentrations of acetic acid and sodium acetate should you use? assuming you wish to make 2 liters of this buffer, how many moles of acetic acid and sodium acetate will you need? how many grams of each will you need (molecular weights: acetic acid 60. 05 g mol 1, sodium acetate, 82. 03 g mol 1)?

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Chemistry, 06.10.2019 02:30, shawdyylinda

Just as ph is the negative logarithm of [h3o+], pka is the negative logarithm of ka, pka=−logka the henderson-hasselbalch equation is used to calculate the ph of buffer solutions: ph=pka+log[base][acid] notice that the ph of a buffer has a value close to the pka of the acid, differing only by the logarithm of the concentration ratio [base]/[acid]. the henderson-hasselbalch equation in terms of poh and pkb is similar. poh=pkb+log[acid][base] part apart complete acetic acid has a ka of 1.8×10−5. three acetic acid/acetate buffer solutions, a, b, and c, were made using varying concentrations: [acetic acid] ten times greater than [acetate], [acetate] ten times greater than [acetic acid], and [acetate]=[acetic acid]. match each buffer to the expected ph. drag the appropriate items to their respective bins. view available hint(s) ph = 3.74 [acetic acid] ten times greater than [acetate] ph = 4.74 [acetate] = [acetic acid] ph = 5.74 [acetate] ten times greater than [acetic acid] previous answers correct part b how many grams of dry nh4cl need to be added to 2.20 l of a 0.400 m solution of ammonia, nh3, to prepare a buffer solution that has a ph of 8.89? kb for ammonia is 1.8×10−5

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Acetic acid has a ka of 1.8ã10â5. three acetic acid/acetate buffer solutions, a, b, and c, were made...

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