You need a 30% alcohol solution. on hand, you have a 200 ml of a 10% alcohol mixture. you also have 55% alcohol mixture. how much of the 55% mixture will you need to add to obtain the desired solution?

160 ml

Explanation:

The expression used will be :

where,

= concentration of Ist alcohol solution= 10%

= concentration of 2nd alcohol solution= 55%

= volume of Ist alcohol solution = 200 ml

= volume of  2nd alcohol solution= v ml

= concentration of resulting alcohol solution= 30%

= volume of resulting alcohol solution= (v+200) ml

Now put all the given values in the above law, we get the volume of added.

By solving the terms, we get :

Therefore, the volume of 55% mixture  needed to be added to obtain the desired solution is 160 ml.

the answer is learned

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