When a 35.07 g sample of phosphorus reacts with oxygen a 71.00 g sample of phosphorus oxide is formed. what is the percent composition of the compound? what is the empirical formula for this compound?

Percentage composition of phosphorus is 43.66%.

Percentage composition of oxygen is 56.66%.

is the empirical formula for this compound.

Explanation:

Moles of phosphorus =

Moles of phosphorus oxide =

1.1312 moles of moles of phosphorus gives z moles of phosphorus oxide.

The from 1 mol phosphorus :

moles of phosphorus oxide...(1)

According to reaction, 2x moles of phosphorus gives 2 mol of phosphorus oxide.

The from 1 mol phosphorus :

moles of phosphorus oxide...(2)

(1)=(2)

The molecular formula of the phosphorus oxide ::

The empirical formula is simplest ratio of elements in a compound.

is the empirical formula for this compound.

Percentage composition of phosphorus =

Percentage composition of oxygen=

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3