Calculate the equilibrium constant for the following reaction: 2cl2(g) + 2h2o(g) ⇌ 4hcl(g) + o2(g) given: 2mgcl2(s) + o2(g) ⇌ 2mgo(s) + 2cl2(g) k = 8.59 mgcl2(s) + h2o(g) ⇌ mgo(s) + 2hcl(g) k = 8.29

Answer : The equilibrium constant for the final reaction will be, 8.00

Explanation :

The following equilibrium reactions are :

(1)      

(2)      

The final equilibrium reaction is :

Now we have to calculate the value of for the final reaction.

First reverse the equation 1 that means we are writing the equilibrium constant as and multiplying the equation 2 by 2 that means we are writing the equilibrium constant as , we get the final equilibrium reaction and the expression of final equilibrium constant is:

Now put all the given values in this expression, we get :

Therefore, the equilibrium constant for the final reaction will be, 8.00

answer:

the reaction is type of combination reaction.

explanation:

on the product side, there are 2 molecules of bonded to fe   which means one atom of fe are combined two molecules of . so, balanced chemical equation becomes :

this reaction follows the reaction type of combination reaction. a combination reaction is defined as chemical reaction in which reactants combines together to form a single product.