Using the periodic table, answer the following question..how many atoms of neon are in 0.378g of neon (a) 6.02 x 10²³ atoms (b) 1.87 x 10‐²atoms (c) 2.28 x 10²³ atoms (d)1.13 x 10²² atoms.

The correct answer is D. 1.13 x 10^22 atoms are present in 0.378 g of neon. Avogadro's number (6.022 x 10^23) gives the ratio of representative particles per mole of substance. For every mole of substance, there are 6.022 x 10^23 representative particles present. Since 0.378 g of neon is less than one mole of neon, the answer should be less than Avogadro's number, which makes option D a logical answer.

Further Explanation:

To get the number of atoms present in 0.378 g of neon the following steps must be done:

STEP 1: Convert 0.378 g of Neon to moles of Neon

STEP 2: Use Avogadro's number to calculate the number of atoms of Ne

Since the given, 0.378 g has 3 significant figures, the final answer must also have 3 significant figures. Therefore,

A. 6.02 x 10^23 atoms is FALSE because the given amount of neon is less than one mole. Hence, the number of atoms cannot be equal to Avogadro's number.

B. 1.187 x 10^-2 atoms is FALSE because atoms are very very small particles. It will require a large number of atoms to make up something that is measurable like a 0.378 g sample of neon. Having less than 1 atom to make up this much sample is not logical.

C. 2.28 x 10^23 atoms is FALSE because this much atoms make up 0.3781 mol of Neon but the given is 0.378 grams not moles of Ne.

D. 1.13 x 10^22 atoms is TRUE because the value is less than 6.022 x 10^23 which is logical since the sample is less than 1 mole.

Learn More

Keywords: Avogadro's Number, Mole Conversion, Atoms