24. which of the following items is false about ionization energy change with removal of valence electrons?

Option C. Na+ has the inert gas structure of argon is false. Sodium has 11 protons and 11 electrons. When it loses an electron and forms Na+, it has 11 protons and 10 electrons. The inert gas that has 10 electrons is Neon not Argon. Argon has 18 electrons.

Further Explanation:

A. Na+ electron configuration is like the stable inert gas configuration - TRUE

Na has an electron configuration of 2,8,1 (or ). When it loses its valence electron, its electron configuration becomes 2,8 (or ). This is similar to the electron configuration of Neon which has a full valence shell. A full valence shell has 8 electrons.

B. To remove the second electron, the increased attraction of protons to electrons must be overcome - TRUE

Ionization energy is the amount of energy needed to remove a valence electron from a gaseous atom. This energy is required to overcome the attraction of the valence electron to the nucleus. The closer the orbital (i.e. the electron), the stronger the attraction of the electrons to the nucleus. Hence, removing a second electron, which is now closer to the nucleus than the first, will require more energy to overcome its stronger attraction to the protons in the nucleus.

C. Na+ has the inert gas structure of Argon - FALSE

The electron structure of Na+ is 2,8 (or ).

The electron structure of Ar is 2,8,8 ( or ).

D. Both A and C are False - FALSE

Only C is false.

E. Items A, B, and C are False - FALSE

A and B are true. Only C is false.

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Keywords: ionization energy, electron configuration

can you list the answers so i can answer