Imagine two solutions with the same concentration and the same boiling point, but one has benzene as the solvent and the other has carbon tetrachloride as the solvent. determine the molal concentration, (or and boiling point, . solvent normal boiling point (∘ (∘/ benzene 80.1 2.53 carbon tetrachloride 76.8 5.03

Hey there!:

Δt =  m * Kf

Boiling point of a solution =>  Boiling point + Δt ( Kc * m )

Boiling point of benzene solution => 80.1 + 2.53 m

Boiling point of CCl₄ solution => 76.8 +5.03 m

Since the boiling points are the same 80.1 + 2.53 m = 76.8 +5.03 m

3.3 = 2.5 m

m =  3.3 / 2.5 => 1.32 moles of solute per kg of solvent

Bp =   80.1 + 2.53 * 1.32 => 83.4396 ºC

Hope this helps!

the answer would be b i believe

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8