Determine how many grams of silver would be produced, if 12.83 x 10^23 atoms of copper react with an excess of silver nitrate. given the equation: cu + 2agno3 -> cu(no3)2 + 2ag avogadro's number: 6.02 x 1023

The amount of silver produced in the given reaction is 459.63 g.

Explanation:

According to mole concept:

1 mole of an atom contains number of atoms.

For the given chemical equation:

By Stoichiometry of the reaction:

1 mole of copper produces 2 moles of silver.

This means that, number of atoms of copper produces number of atoms of silver.

So, number of atoms of copper will produce = number of atoms of silver.

We know that:

Mass of 1 mole of silver = 107.87 g

Using mole concept:

If, number of atoms occupies 107.87 grams of silver atom.

So, number of atoms will occupy =

Hence, the amount of silver produced in the given reaction is 459.63 g.

i need mutiple choices