(edta4-) is used as a complexing agent in chemical analysis. solutions of edta4- are used to treat heavy metal poisoning by removing the heavy metal in the form of a soluble complex ion. the complex [pb(edta]2- has kf = 1.1 x 1018.
a. calculate the concentration of pb2+ in a saturated solution of pb(oh)2, ksp = 1.2 x 10-15.
b. calculate the concentration of pb2+ in a saturated solution of pb(oh)2 buffered at ph 13.00
c. calculate the concentration of pb2+ in a 1.0 l solution containing 0.050 m na4edta with 0.010 mole pb(no3)2 added (assume negligible volume change due to addition of this solid).
d. consider a solution with 0.010 mole pb(no3)2 added to 1.0 l of an aqueous solution buffered at ph = 13.00 and also containing 0.050 m na4edta. does pb(oh)2 precipitate from this solution?

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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