What is the volume of an oxygen tank if it contains 12 moles of oxygen at 273k under 75kpa?

Explanation:

Given parameters:

Number of moles = 12moles

Temperature = 273K

Pressure = 75kPa, convert to atm:

                  1kPa = 0.00986923atm

                   75kPa = 75 x 0.00986923 = 0.74atm

Unknown:

Volume of the oxygen gas

Solution:

We simply apply the idea gas law which is :

                            PV = nRT

  Since the unknown is volume, we make it the subject of the formula:

                             V =

R is the gas constant and its value is given as 0.082

           V = = 363.01L

it is the most commonly accepted one